USCG Exam PracticeDC circuits and electronic principles
Three resistors — 6 Ω, 12 Ω, and 4 Ω — are connected in series across a 44 V source. What is the current flowing through the 12 Ω resistor?
- ✓ 2 ACorrect
- B. 3.67 A
- C. 11 A
- D. 1.57 A
Why A is correct
Total series resistance is 6 + 12 + 4 = 22 Ω. By Ohm's law, I = E/R = 44/22 = 2 A. In a series circuit the same current flows through every component, so the 12 Ω resistor also carries 2 A. (NEETS Mod. 1 §3-2, NEETS Mod. 1 §3-1)