USCG Exam PracticeDC circuits and electronic principles
A DC circuit contains a series resistor of 500 Ω and an inductor of 2.5 H. Approximately how long after the source is applied will the current reach 63% of its steady-state value?
- ✓ 0.005 secondsCorrect
- B. 1,250 seconds
- C. 0.025 seconds
- D. 200 seconds
Why A is correct
The RL time constant is T = L/R = 2.5 H / 500 Ω = 0.005 seconds. After one time constant the current reaches approximately 63% of its final steady-state value. (NEETS Mod. 2 §2-2)
Cited:NEETS Mod. 2 §2-2