USCG Exam PracticeDC circuits and electronic principles
Three resistors — 6 Ω, 12 Ω, and 4 Ω — are connected in series across a 44 V source. What is the voltage drop across the 12 Ω resistor?
- ✓ 24 VCorrect
- B. 12 V
- C. 14.67 V
- D. 22 V
Why A is correct
Total resistance = 6 + 12 + 4 = 22 Ω. Series current = 44 V / 22 Ω = 2 A. Voltage across 12 Ω = 2 A × 12 Ω = 24 V. In a series circuit the same current flows through every element and each drop is found by Ohm's law using that common current. (NEETS Mod. 1 §3-2)
Cited:NEETS Mod. 1 §3-2