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USCG Exam PracticeAC circuits and theory

A shipboard AC load draws 100 A at 440 V with a power factor of 0.75 lagging. What is the true (real) power consumed by this load?

  1. A. 44,000 W
  2. ✓ 33,000 WCorrect
  3. C. 58,667 W
  4. D. 75,000 W

Why B is correct

True power = E × I × cos θ = 440 × 100 × 0.75 = 33,000 W. Option A is the apparent power (VA), which does not account for power factor. Per NEETS Mod. 2 §4-2, only the in-phase component does real work.

Cited:NEETS Mod. 2 §4-2

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A shipboard AC load draws 100 A at 440 V with a power factor of 0.7… — USCG Exam Practice · CaptainsGround